# Statistics (VVN)

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1 . Define time series. Describe moving average method.
2 . What do you mean by Primary & Secondary data. What are the methods to collect them ?
3 . What is a Hypothesis ? Write the procedure for testing a Hypothesis.
4 . What is the diffrence between census & sample survey. Write steps in sampling design.
5 . A biased coin is tossed 6 times. The probability of heads on any toss is 0.3. Let X denote the number of heads that come up. Calculate: (i) P(X = 3) (ii) P(1 < X ≤ 5) 6 . The number of calls coming per minute into a hotels reservation center is Poisson random variable with mean 3. Find the probability that no calls come in a given 1 minute period. 7 . The local ice cream shop keeps track of how much ice cream they sell versus the temperature on that day, here are their figures for the last 12 days: Ice Cream Sales vs Temperature Temperature °C Ice Cream Sales 14.2° \$215 16.4° \$325 11.9° \$185 15.2° \$332 18.5° \$406 22.1° \$522 19.4° \$412 25.1° \$614 23.4° \$544 18.1° \$421 22.6° \$445 17.2° \$408 Find Karl Pearson’s coefficient of correlation between temperature & sales . 8 . A company is involved in the production of two items (X and Y). The resources need to produce X and Yare twofold, namely machine time for automatic processing and craftsman time for hand finishing. The table below gives the number of minutes required for each item: Machine time Craftsman time Item X 13 20 Item Y 19 29 The company has 40 hours of machine time available in the next working week but only 35 hours of craftsman time. Machine time is costed at £10 per hour worked and craftsman time is costed at £2 perhour worked. Both machine and craftsman idle times incur no costs. The revenue received for each item produced (all production is sold) is £20 for X and £30 for Y. The company has a specific contract to produce 10 items of X per week for a particular customer. Formulate the problem of deciding how much to produce per week as a linear program. Case Detail : The length of life of an instrument produced by a machine has a normal ditribution with a mean of 12 months and standard deviation of 2 months. Find the probability that an instrument produced by this machine will last 1. between 7 and 12 months. 2. less than 7 months. 3. more than 5 months but less than 10 months Question No. 1 The mean age of combined group of men and women is 25 years. If the mean age of group of men is 26 and that of group of women is 21, then percentage of men and women in the group respectively is: Options 60,40 80,20 30,70 50,50 Question No. 2 What is the weighted mean of first 10 natural numbers whose weights are equal to the corresponding number? Options 7 5,5 5 4,5 Question No. 3 Sum of mode and median of the data Options 26 31 28 41 Question No. 4 The mean of 9 observations is 16. One more observation is included and the new mean becomes 17. The 10th observation is Options 18 30 7 26 Question No. 5 Given third quartile is 80 & first quartile is 20 then semi-inter quartile range is Options 100 60 30 40 Question No. 6 Given third quartile is 100 & first quartile is 25 then coefficient of Quartile Deviation Options 6 75 0.6 125 Question No. 7 Given mean is 45 & standard deviation is 15 then coefficient of variation is Options 30 33.33 34 33 Question No. 8 Given, covariance of (x ,y )=10 variance of x =49,variance of y =100,correlation between x and y is Options 5/8 7/8 1/3 1/7 Question No. 9 Coefficient of non-determination is Options 1-r2 r2 -1 r2 1+ r2 Question No. 10 In binomial probability distribution, the dependents of standard deviations must includes Options probability of q probability of p Trials all options Question No. 11 The formula to calculate standardized normal random variable is Options x + μ ⁄ σ x - μ ⁄ σ x - σ ⁄ μ x + σ ⁄ μ Question No. 12 In binomial distribution, the formula of calculating standard deviation is Options square root of p square root of pq square root of npq square root of np Question No. 13 The tail or head, the one or zero and the girl and boy are examples of Options non functional events complementary events non complementary events functional events Question No. 14 The method of calculating skewness which is based on the positions of quartiles and median in a distribution is called Options Gary's coefficient of skewness Sharma's coefficient of skewness Bowley's coefficient of skewness Jack Karl's coefficient of skewness Question No. 15 The median of a moderately skewed distribution is 8, third quartile is 12, first quartile is 8 and inter-quartile range is 4 then relative coefficient of skewness is Options ±8 ±1 ±9 ±11 Question No. 16 The kurtosis defines the peakness of the curve in the region which is Options around the mode around the mean around the median around the variance Question No. 17 In measures of skewness, the absolute skewness is equal to Options mean+mode mean-mode mean+median mean-median Question No. 18 If for a distribution the difference of first quartile and median is less than difference of median and third quartile then the distribution is classified as Options negatively skewed not skewed at all absolute open ended positively skewed Question No. 19 The three times of difference between mean and median is divided by standard deviation to calculate coefficient of skewness by method of Options Professor Keller Professor Kelly Karl Pearson Professor Bowley Question No. 20 If the standard deviation of the population is 35 and the sample size is 9 then the standard deviation of sampling distribution is Options 12.67 11.67 13.67 14.67 Question No. 21 In statistical analysis, the sample size is considered large if Options n > or = 30
n < or = 30 n > or = 40
n < or = 50 Question No. 22 If the mean of population is 25 then the mean of sampling distribution is Options 50 25 30 20 Question No. 23 The standard deviation of a sampling distribution is also classified as Options standard error statistic error sampling error probability error Question No. 24 In sampling distribution, the formula of calculating standard deviation of sample proportion is as Options square root of pqn ⁄ p square root of pn ⁄ q square root of nq ⁄ p square root of pq ⁄ n Question No. 25 The numerical methods and graphical methods are specialized procedures used in Options social statistics education statistics descriptive statistics business statistics Question No. 26 The focus groups, individual respondents and panels of respondents are classified as Options pointed data sources itemized data sources secondary data sources primary data sources Question No. 27 The collection of all the elements such as group of variables for research is classified as Options statistical process population data marginal error Question No. 28 In linear programming, the constraints can be represented by Options equalities inequalities ratios both 1 and 2 Question No. 29 The feasible region's optimal solution for a linear objective function always includes Options downward point upward point corner point front point Question No. 30 The objective of linear programming for an objective function is to Options subset or proper set modeling maximize or minimize row or column modeling adjacent modeling Question No. 31 In linear programming, the objective function and objective constraints are Options quadratic solved linear adjacent Question No. 32 In maximization problem, the optimal solution occurring at the corner point yields the Options mean values of z mid values of z lowest value of z highest value of z Question No. 33 If the arithmetic mean is multiplied to coefficient of variation then the resulting value is classified as Options coefficient of deviation coefficient of mean standard deviation variance Question No. 34 The formula of coefficient of range is Options L+L ⁄ H+H H+l ⁄ H-L H-L ⁄ H+L H+H ⁄ L+L Question No. 35 Considering the standard deviation, the mean absolute deviation is equal to Options 5⁄4 σ 7⁄8 σ 5⁄8 σ 4⁄5 σ Question No. 36 The sum of highest and lowest value is 80 and the coefficient of range is 0.625 then the difference between highest and lowest value is Options 50 70 80 48 Question No. 37 The value of third quartile is 61 and inter quartile range of the set of observation is 48 then value of first quartile is Options 24 34 64 13 Question No. 38 Which is the best method to find trend Options free hand least square moving average semi average Question No. 39 Components of time series are Options T,S,C.I T,S.P.I T,C,S,P T,I,C.P Question No. 40 Regression lines intersect at Options mean values median mode correlation We Also Provide SYNOPSIS AND PROJECT. Contact www.kimsharma.co.in for best and lowest cost solution or Email: solvedstudymaterial@gmail.com Call: +91 82907-72200 (Call/WhatsApp) or +91 88003-52777 (WhatsApp Only)